Question

5m Breadth 28m perimeter find length​

Answer 1

Given:-

• Breadth of a rectangle is 5 m.
• Perimeter of a rectangle is 28 m.

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To find:-

• Length of a rectangle.

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Solution:-

Let,

• the length of a rectangle be l.

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Here,

• Breadth (b) = 5 m
• Perimeter = 28 m

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According to the question

★Formula used:-

Perimeter of rectangle = 2(length + breadth)

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→ 28 = 2(l + b)

→ 28 = 2(l + 5)

→ 28/2 = l + 5

→ 14 = l + 5

→ l = 14 - 5

→ l = 9 m

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Hence,

• the length of a rectangle is 9 m.

Answer 2

Given - Breadth and perimeter of a rectangle are 5m and 28m respectively.

We've to find the length of the rectangle.

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✰ Let the length of the rectangle = l

As we know that :

$\underline{\boxed{\tt\purple{\bigstar \: perimeter \: of \: a \: rectangle \: = 2(l + b)}}}$

Where

• l = length
• b = breadth

Now,

$\tt:\implies \: perimeter \: of \: the \: rectangle \: = 2(l + b) \\ \\ \\ \tt:\implies \: 28 = 2(l + 5) \\ \\ \\ \tt:\implies \: \cancel\frac{28}{2} = l + 5 \\ \\ \\ \tt:\implies \: 14 = l + 5 \\ \\ \\ \tt:\implies \: l = 14 - 5 \\ \\ \\ \tt:\implies \: l = \underline{\boxed{\tt\purple{9cm}}}\bigstar \\ \\ \\ \sf\therefore{\underline{Hence, the\: length \: of \: the \: rectangle \: is \: \bold{9cm}. }}$