5m-n=3m+4n then find value of m2+n2/m2-n2
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Answer:
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Step-by-step explanation:
If
5m-n = 3m+4n
=》 5m-3m = 4n+n
=》 2m = 5n
=》 m = 5n/2
So,
(m^2 + n^2)/(m^2 - n^2)
= [{25(n^2)/4}+{n^2}]/[{25(n^2)/4}-{n^2}]
= (29n^2)/(21n^2)
= 29/21
SO,
29/21
IS YOUR ANSWER
HOPE IT HELPS......
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