Question

5m of a solution contains 15%(w/w) nitric acid. Find its density

Answer 1

let volume of solution be 1 L
so 5 moles of nitric acid are there in 1 L solution
so weight of nitric acid =5*(1+14+48)=315g
weight of solution=1000*density
weight of solute =0.15*1000*density=315
density=2.1g/cm³

Answer 2

Answer:

Explanation:

let volume of solution be 1 L

so 5 moles of nitric acid are there in 1 L solution

so weight of nitric acid =5*(1+14+48)=315g

weight of solution=1000*density

weight of solute =0.15*1000*density=315

density=2.1g/cm³