5n×25n-1÷(5n-1×25n-1)
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5n × 25n -1 ÷ ( 5n -1 × 25n -1)
= 125n^2 - 1 ÷ ( 5n - 25n -1)
= 125n^2 - 1 ÷ (-20n) -1
( Multiply the whole expression by n in order to remove n from the denominator)
= 125n^3 + 1/20 - n
= 2500n^3 + 1 -20n
The answer is 2500n^3 +1 - 20n.
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Hope it helps ! ^_^
= 125n^2 - 1 ÷ ( 5n - 25n -1)
= 125n^2 - 1 ÷ (-20n) -1
( Multiply the whole expression by n in order to remove n from the denominator)
= 125n^3 + 1/20 - n
= 2500n^3 + 1 -20n
The answer is 2500n^3 +1 - 20n.
__________________________________
Hope it helps ! ^_^
Answered by
2
⊂5n×25n⊃-1÷5n⊂25n-1⊃-1⊂25n-1⊃ =125n-1÷125n whole square-1-25n+1 =125n-1÷125n whole square -1-25+1 =1÷100n
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