Question

5n+3-6*5n+1/9*5x-2 square*5n​

Answer 1

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Answer 2

Answer:

$\frac{ {(5)}^{n + 3} - 6 \times {(5)}^{n + 1} }{9 \times {5}^{n} - {2}^{2} \times {5}^{n} } \\ \\ = \frac{{(5)}^{n + 3} \times - 6 \times {(5)}^{n + 1} }{ {5}^{n} (9 - {2}^{2}) } \\ \\ = \frac{ {5}^{n}( {5}^{3} - (6 \times {5}^{1} )) }{ {5}^{n} ( {3}^{2} - {2}^{2}) } \\ \\ = \frac{ \cancel{ {5}^{n}}( {5}^{3} - (6 \times {5}^{1} )) }{ \cancel{ {5}^{n}} ( {3}^{2} - {2}^{2}) } \\ \\ = \frac{ {5}^{3} - (6 \times 5) }{9 - 4} \\ \\ = \frac{125 - 30}{5} \\ \\ = \frac{95}{5} \\ \\ \boxed{ = \underline{ \underline{ \bf 19}}}$