Question

5n-3(n-2)=3n-2(n-1) .simplify and find the value of n

Answer 1

It can be written as , {3^n + (3^n * 3^1) } / { 3^n + (3^n * 3^-1)}

By taking 3^n common,

3^n {1 + 3^1} / 3^n { 1 + 3^-1}

Cancelling 3^n ,

{1 + 3 } / { 1 + 1/3 }

=> 4 / {4/3}

=>{ 4 *3} / 4

=> 3. answer

Answer 2

Heya!!!!

Answer to your question:

5n-3(n-2)=3n-2(n-1)

5n-3n+6=3n-2n+2

2n+6=n+2

n=-4

Hope it helps ^_^