Math, asked by mowmitadas12, 1 day ago

5n²+75n-1620=0

Factorisation.​

Answers

Answered by rohitsharmabp56
0

Answer:

my dear friend your answer is t

Step-by-step explanation:

Common factor

5

2

+

7

5

1

6

2

0

=

0

5n^{2}+75n-1620=0

5n2+75n−1620=0

5

(

2

+

1

5

3

2

4

)

=

0

5(n^{2}+15n-324)=0

5(n2+15n−324)=0

2

Divide both sides of the equation by the same term

5

(

2

+

1

5

3

2

4

)

=

0

5(n^{2}+15n-324)=0

5(n2+15n−324)=0

2

+

1

5

3

2

4

=

0

n^{2}+15n-324=0

n2+15n−324=0

3

Use the quadratic formula

=

±

2

4

2

n=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

n=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

+

1

5

3

2

4

=

0

n^{2}+15n-324=0

n2+15n−324=0

=

1

a={\color{#c92786}{1}}

a=1

=

1

5

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