Question

(5p+1)(p+4)=2(7p+5) what is the value of p ?

Answer 1

Answer:

On opening the bracket we get

5p²+20p+p+4=14p+10

5p²+7p-6=0

5p²+10p-3p-6=0

5p(p+2)-3(p+2)=0

(5p-3)(3p+2)=0

So, p=-2/3, 3/5

Step-by-step explanation:

Answer 2

Answer:

x=-2, x=3/5

Step-by-step explanation:

MULTIPLY both

${5p}^{2} + 21p + 4 = 14p + 10$

Rearrange And Solve The Quadritic

${5p}^{2} + 7p - 6 = 0$