(5p^2-25p+20/p-1
pls answer fast
Answers
Answered by
0
Answer:
(5p 2−25p+20)÷5(p−4)
⇒5p 2 −25p+20=5(p 2 −5p+4)
=5[p 2 −4p−p+4]
=5[p(p−1)−4(p−1)]
=5[(p−1)(p−4)]
∴ (5p 2 −25p+20)÷(p−1)= (p−1)5(p−1)(p−4) =5(p−4).
∴(5p2 −25p+20)÷(p−1)=5(p−4).
Answered by
0
Step-by-step explanation:
(5p2−25p+20)÷5(p−4)
⇒5p2−25p+20=5(p2−5p+4)
=5[p2−4p−p+4]
=5[p(p−1)−4(p−1)]
=5[(p−1)(p−4)]
∴ (5p2−25p+20)÷(p−1)=(p−1)5(p−1)(p−4)
=5(p−4).
∴(5p2−25p+20)÷(p−1)=5(p−4).
Similar questions