Math, asked by akshaykrishnakumar05, 1 month ago

(5p^2-25p+20/p-1


pls answer fast

Answers

Answered by brainly10038
0

Answer:

(5p 2−25p+20)÷5(p−4)

⇒5p 2 −25p+20=5(p 2 −5p+4)

=5[p 2 −4p−p+4]

=5[p(p−1)−4(p−1)]

=5[(p−1)(p−4)]

∴ (5p 2 −25p+20)÷(p−1)= (p−1)5(p−1)(p−4) =5(p−4).

∴(5p2 −25p+20)÷(p−1)=5(p−4).

Answered by shrutikshajadhav
0

Step-by-step explanation:

(5p2−25p+20)÷5(p−4)

⇒5p2−25p+20=5(p2−5p+4)

=5[p2−4p−p+4]

=5[p(p−1)−4(p−1)]

=5[(p−1)(p−4)]

∴ (5p2−25p+20)÷(p−1)=(p−1)5(p−1)(p−4)

=5(p−4).

∴(5p2−25p+20)÷(p−1)=5(p−4).

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