Question

5p-2[p-3(p-5)]=6 Linear equations with one variable

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Answer 1

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step-by-step explanation:

Let's start by solving the parenthesis.

We have two types of parenthesis over here but "( )" round brackets are given priority.

So, it becomes:-

5p-2[p - 3p + 15] = 6

Now open the "[ ]" Square Brackets:-

5p - 2p +  6p - 30 = 6

Add the like terms:-

9p - 30 = 6

Transpose to the right hand side:-

9p = 36

p = 4

So, the value of p is 4 !

Answer 2

5p -2(p-3p+15)=6

5p -2p+6p-30=6

9p-30=6

9p=6+30

9p=36

p=36÷9

p=4

《Check》

Now,P=4

5×4-2[4-3(4-5)]=6

20-2(4-12+15)=6

20-2(+7)=6

20-14=6

6=6

《《Hence checked》》

I hope it will help u...