CBSE BOARD X, asked by nuppuursinhg, 10 months ago

5p-2[p-3(p-5)]=6 Linear equations with one variable

Answers

Answered by Anonymous
0
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step-by-step explanation:


Let's start by solving the parenthesis.

We have two types of parenthesis over here but "( )" round brackets are given priority.

So, it becomes:-

5p-2[p - 3p + 15] = 6

Now open the "[ ]" Square Brackets:-

5p - 2p +  6p - 30 = 6

Add the like terms:-

9p - 30 = 6

Transpose to the right hand side:-

9p = 36

p = 4

So, the value of p is 4 !
Answered by Anonymous
0

HOLA MATE..... ❤

step-by-step explanation:

Let's start by solving the parenthesis.

We have two types of parenthesis over here but "( )" round brackets are given priority.

So, it becomes:-

5p-2[p - 3p + 15] = 6

Now open the "[ ]" Square Brackets:-

5p - 2p + 6p - 30 = 6

Add the like terms:-

9p - 30 = 6

Transpose to the right hand side:-

9p = 36

p = 4

So, the value of p is 4 !

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