Question

5p2+(-20p-5p)+20÷(p-1)​

Answer 1

Answer:

(5p2−25p+20)÷5(p−4)

⇒5p2−25p+20=5(p2−5p+4)

=5[p2−4p−p+4]

=5[p(p−1)−4(p−1)]

=5[(p−1)(p−4)]

∴ (5p2−25p+20)÷(p−1)=(p−1)5(p−1)(p−4)

=5(p−4).

∴(5p2−25p+20)÷(p−1)=5(p−4).

Answer 2

Answer:

FAQs on GCF of 24 and 80

FAQs on GCF of 24 and 80The GCF of 24 and 80 is 8. To calculate the greatest common factor (GCF) of 24 and 80, we need to factor each number (factors of 24 = 1, 2, 3, 4, 6, 8, 12, 24; factors of 80 = 1, 2, 4, 5, 8, 10, 16, 20, 40, 80) and choose the greatest factor that exactly divides both 24 and 80, i.e., 8.