Question

(5p2-25p+20)÷(p-1) how to solve this question

Answer 1

Given Equation is:

$\frac{5p^2-25p+20}{p-1}$

$\frac{5(p^2 - 5p + 4)}{(p-1)}$

$\frac{5(p-1)(p-4)}{(p-1)}$

5(p-4).


Hope this helps!

Answer 2

On dividing (5p²-25p+20) by (p-1) we get (5p - 20)

Given:

(5p²-25p+20) ÷ (p-1)  

To find:

Solve (5p²-25p+20) ÷ (p-1)  

Solution:

To divide (5p²-25p+20) by (p-1)    

Factorize the 5p²-25p+20 as follows

=> 5p²-25p+20    

=> 5p²- 5p - 20p+20     [ Split the middle term ]

=> 5p (p - 1) - 20(p - 1)    [ grouping the terms ]

=> (p - 1) (5p - 20)    

=>  (5p²-25p+20)/(p-1)  = (p - 1) (5p - 20)/(p-1) = 5p - 20

Therefore,

On dividing (5p²-25p+20) by (p-1) we get (5p - 20)

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https://brainly.in/question/1171187  

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