Math, asked by kgafelareabetswe, 1 month ago

(5p²q+pq²-6)+(-p²q-7)+(-pq²+14)​

Answers

Answered by akaftab12345
1

Answer:

I hope this will help you. Thank you

Attachments:
Answered by maityh73
1

Answer: 4(p^2)q + 1

Step-by-step explanation:

(5(p^2)q + p(q^2) -6) + (-(p^2)q -7) + (-p(q^2) + 14)

= ( (p^2)q x (5 - 1) ) + ( p(q^2) × (1 -1) )

+ ( -6 -7 +14)

= 4(p^2)q + 1

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