(5p²q+pq²-6)+(-p²q-7)+(-pq²+14)
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Answered by
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Answer: 4(p^2)q + 1
Step-by-step explanation:
(5(p^2)q + p(q^2) -6) + (-(p^2)q -7) + (-p(q^2) + 14)
= ( (p^2)q x (5 - 1) ) + ( p(q^2) × (1 -1) )
+ ( -6 -7 +14)
= 4(p^2)q + 1
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