Question

5pairs of integers(a,b) such that a/b=-2

Answer 1

Step-by-step explanation:

• We have the condition that :-
• If a and b are two numbers then 1/b = -2.
• First of all we have to decide that what are those numbers which when divided , gives the quotient-2.
• So we can find this by the following method:-
• First remind the multiplication table of 2.
• e.g.= 2×1=2
• 2×2=4
• 2×3=6
• 2×4=8
• 2×5=10
• We have to find 5 pairs of numbers.
• Hence we reimind the table of 2 upto 5.
• Now as we have the quotient in minus hence we have to put a minus sign in the numerators.
• Now if we divide the products of table 2 by the factor except 2 and put a minus sign in each case, we can get our required solution.
• So 5 pairs of numbers are:-

1. -2/1=-2
2. -4/2=-2
3. -6/3=-2
4. -8/4=-2
5. -10/5=-2.

Hence our required numbers are:-

(-2,1),(-4,2),(-6,3),(-8,4),(-10,5)