Math, asked by sheerazkhanchachar12, 6 days ago

5r^2+2r_3=0 factoring method​

Answers

Answered by krishnakalpanadash
0

Step-by-step explanation:

5r²+2r-3

5×3=15

5r²+5r-3r-3

5r(r+1)-3(r+1)

(5r-3)(r+1)

Answered by manojmn740
0

Answer:

multiply first and last term than take factor to +2

Step-by-step explanation:

we get

5r‹2+2r-3=0

5r‹2+5r-3r-3=0

take 5r and -3 common we get

5r(r+1)-3(r+1)=0

therefore ,

(r+1)(5r-3)=0

then,,

r=-1,5r=3

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