Math, asked by arpit123446, 5 months ago

5sec2A – 5 tan2A =


(a) 1

(b) 5

(c) 9

(d)0​

Answers

Answered by psupriya789
2

Answer:

5

Step-by-step explanation:

5sec2A - 5 tan2A

TAKING COMMON

5[sec2A-tan2A]

5[1]

=5

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