5sin ²A +5 cos²A = 5
Answers
Answered by
2
Step-by-step explanation:
5sin ²A +5 cos²A = 5
> 5 (sin ²A + cos²A) = 5
> sin ²A + cos²A = 1
> 1 = 1
Therefore, LHS = RHS.
Hence, the equation is completely true.
Answered by
0
Answer:
secA=
2
secA=sec45
A=45
∘
4tan
2
A−sin
2
A
3cos
2
A+5tan
2
A
=
4tan
2
45−sin
2
45
3cos
2
45+5tan
2
45
=
4(1)
2
−(
2
1
)
2
3(
2
1
)
2
+5(1)
2
=
4−
2
1
2
3
+5
=
2
7
2
13
=
7
13
= 1
7
6
Therefore value of m is 7.
please mark my ans as Brainlist
Similar questions