Math, asked by kajal171279, 6 months ago

5sin² 30+Sin² 45- 4tan² 30⁰ ÷ 2sin 30cos30+cot45​

Answers

Answered by kbheemashankar23
3

Answer:

5sin²30+sin²45-4tan²30÷2sin30cos30+cot45

=5(1/2)²+(1/√2)²-4(1/√3)²÷2(1/2)(√3/2)+1

=5(1/4)+(1/2)-4(1/3)÷2√3/4+1

=5/4+1/2-4/3÷√3/2+1

=7/4-4/3÷√3+2/2

=5/12÷√3+2/2

=5/12×2/√3+2

=5/6√3+12

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