5sin30°+cos²45°-4tan²30°/2sin30°×cos30°+tan45°
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16
Answer:
5sin30°+cos²45°-4tan²30°/2sin30°×cos30°+tan45°
Answered by
0
Answer:
We have,
2sin30
∘
cos30
∘
+tan45
∘
5sin
2
30
∘
+cos
2
45
∘
−4tan
2
30
∘
=
2×
2
1
×
2
3
+1
5×(
2
1
)
2
+(
2
1
)
2
−4×(
3
1
)
2
=
2
3
+1
4
5
+
2
1
−
3
4
=
2
3
+2
12
5
=
12
5
×
(
3
+2)
2
=
6(2+
3
)
5
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