Question

5sin76sec14+3cot70-cot20+5tan45

Answer 1

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Answer 2

SOLUTION

TO EVALUATE

5sin 76° sec 14° + 3 cot 70° cot 20° + 5 tan 45°

EVALUATION

5sin 76° sec 14° + 3 cot 70° cot 20° + 5 tan 45°

= 5sin(90°-14°) sec 14° + 3 cot(90°-20°) cot 20° + 5×1

= 5 cos 14° sec 14° + 3 tan 20° cot 20° + 5

= 5 + 3 + 5

$= 13$

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