Math, asked by ankitbhankher, 6 months ago

5t^2-20t-100=0 how to slove​

Answers

Answered by JivanPPatel
0

This Question is solve by hand.

please make this answer as brainest.

Answered by Anonymous
5

Answer:

Simplifying

5t2 + 20t = 100

Reorder the terms:

20t + 5t2 = 100

Solving

20t + 5t2 = 100

Solving for variable 't'.

Reorder the terms:

-100 + 20t + 5t2 = 100 + -100

Combine like terms: 100 + -100 = 0

-100 + 20t + 5t2 = 0

Factor out the Greatest Common Factor (GCF), '5'.

5(-20 + 4t + t2) = 0

Ignore the factor 5.

Subproblem 1

Set the factor '(-20 + 4t + t2)' equal to zero and attempt to solve:

Simplifying

-20 + 4t + t2 = 0

Solving

-20 + 4t + t2 = 0

Begin completing the square.

Move the constant term to the right:

Add '20' to each side of the equation.

-20 + 4t + 20 + t2 = 0 + 20

Reorder the terms:

-20 + 20 + 4t + t2 = 0 + 20

Combine like terms: -20 + 20 = 0

0 + 4t + t2 = 0 + 20

4t + t2 = 0 + 20

Combine like terms: 0 + 20 = 20

4t + t2 = 20

The t term is 4t.  Take half its coefficient (2).

Square it (4) and add it to both sides.

Add '4' to each side of the equation.

4t + 4 + t2 = 20 + 4

Reorder the terms:

4 + 4t + t2 = 20 + 4

Combine like terms: 20 + 4 = 24

4 + 4t + t2 = 24

Factor a perfect square on the left side:

(t + 2)(t + 2) = 24

Calculate the square root of the right side: 4.898979486

Break this problem into two subproblems by setting  

(t + 2) equal to 4.898979486 and -4.898979486.

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