Question

5t^2 −4t−5=0

How do we get the below solution of the above equation?

(t+1)(t−5)=0
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Answer 1

Instead of 5t^2 it should be only t^2

Then by factorization method

t^2-4t-5=0

t2 - 5t + t - 5

t(t-5) +1(t-5)

(t+1) (t-5)=0...

Hope it helped u...

Answer 2

Step-by-step explanation:

$5 {t}^{2} - 4t - 5 = 0 \\ this \: cannot \: give \: the \: desired \: output \\ \\ you \: have \: to \: correct \: the \: equation \\ \\ if \: you \: take \: \\ {t}^{2} - 4t - 5 = 0 \\ then \: you \: will \: get \: the \: desired \: output \\ \\ {t}^{2} - 4t - 5 = 0 \\ {t}^{2} - 5t + t - 5 = 0 \\ t(t - 5) + 1(t - 5) = 0 \\ (t + 1)(t - 5) = 0$