Question

5t²-10t+120=0 find their components

Answer 1

Step-by-step explanation:

Given

${5t}^{2} - 10t + 120 = 0$

Now ,

$= 5( {t}^{2} - 2t - 24) = 0$

$=> {t}^{2} - 2t - 24 = 0$

by splitting the middle term

$=> {t}^{2} - 6t + 4t - 24$=0

$=> t(t - 6) + 4(t - 6)$=0

$\: now \: at \: the \: end \: of \: step$

$= (t - 6)(t + 4) = 0$

Hope it helps you