5t²-11t - 4 = 0 pls explain this pls
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U can find that using -b+or-root b^2-4ac/2a
Where,a=5,b=11,c=4
Where,a=5,b=11,c=4
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Step-by-step explanation:
In this equation it tells that the coefficient of the variable with power 1 ,i.e.,t should have the constant coefficient which must be the sum of those numbers whose product is 5×-4=-20.
But here we find no such numbers whose product is -20 and sum is -11
So it may have an imaginary root or may have no roots.
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