5t2-20t-25 solve this in brief
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Answer:
I am considering this polynomial as equation for solving, i.e,
5t^2-20t-25=0,
=>5t^2-25t+5t-25=0,
=>5t(t-5)+5(t-5)=0,
=>(5t+5)(t-5)=0,
then,
5t+5=0,
=>t=-1.
(or)
t-5=0,
=>t=5.
therefore, t will be either 5 or -1
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