5tanA=4 then 5tanA-3cosA÷5tanA+2cosA=?
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Answer:
tan A = 4/5 = p/b
h=√4²+5+
=√16+25
=√41
5sinA-3cosA / 5sinA+2cosA
=5×4/√41-3×5/√41 / 5×4/√41+ 2×5/√41
=20/√41-15/√41 / 20/√41+10/√41
=20-15/√41 ÷ 20+10/√41
=5/√41 × √41/30
=5/30
=1/6
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