Question

5tanx-4=0, then the value of 5sin x-4cosx/5sinx+4cosx is

Answer 1

Answer:

given:5tanx-4=0

then,,

= 5sinx-4cosx/5sinx+4cosx :

divide both numerator and denominator by cos x

We get,

=5tanx-4/5tanx+4

then value of 5tanx-4 get zero

and answer is

= 0.

Answer 2

$5 tan x - 4 = 0 \\\\ So, \: tanx = \frac{4}{5} \\\\\we\:have\:to\: find \: value \: of \:( 5 sinx - 4 cosx ) \div (5 sinx + 4 cosx ) \\\\Take \: cos x \:as \: common, \: \\\\ \frac{ cosx(5tanx - 4)}{cosx(5 \tan x + 4 )} \\\\ We \: have \: now \: \\\\ \frac{ (5 tanx - 4)}{(5 tanx + 4)} \\\\ Now, \: put \: the \: value \: of \: tanx = \frac{4}{5} \\\\ \: we \: get \: answer \: 0$