5th class divisibility rules
Answers
Answer:
To make solving quicker and easier, we can apply the divisibility rule of 5, which states that if a number ends in 0 or 5, we can divide it by 5. In other words, we can make equal groups without a remainder. Take look at these images, which test the divisibility rule of 5 for the number 5 and the number 10.
Answer:
To make solving quicker and easier, we can apply the divisibility rule of 5, which states that if a number ends in 0 or 5, we can divide it by 5. In other words, we can make equal groups without a remainder. Take look at these images, which test the divisibility rule of 5 for the number 5 and the number 10.
Divisibility by 1
Every number is divisible by 1. Divisibility rule for 1 doesn’t have any particular condition. Any number divided by 1 will give the number itself, irrespective of how large the number is. For example, 3 is divisible by 1 and 3000 is also divisible by 1 completely.
Divisibility by 2
Any even number or number whose last digit is an even number i.e. 2,4,6,8 including 0 is always completely divisible by 2.
Divisibility Rules for 3
Divisibility rule for 3 states that a number is completely divisible by 3 if the sum of its digits is divisible by 3 i.e., it is a multiple of 3
Consider a number, 308. To check whether 308 is divisible by 3 or not, take sum of the digits (i.e. 3+0+8= 11). Now check whether the sum is divisible by 3 or not. If the sum is a multiple of 3 then the original number is also divisible by 3. Here, since 11 is not divisible by 3, 308 is also not divisible by 3.
Similarly, 516 is divisible by 3 completely as the sum of its digits i.e. 5+1+6=12, is a multiple of 3.
Divisibility by 4
If the last two digits of a number are divisible by 4, then that number is a multiple of 4 and is divisible by 4 completely.
Example: Take the number 2308. Consider the last two digits i.e. 08. As 08 is divisible by 4, the original number 2308 is also divisible by 4.
Divisibility by 5
Numbers with last digit 0 or 5 are always divisible by 5.
Example: 10, 10000, 10000005, 595, 396524850 etc.
Divisibility by 6
Numbers which are divisible by both 2 and 3 are divisible by 6. That is, if last digit of the given number is even and the sum of its digits is a multiple of 3, then the given number is also a multiple of 6.
Example: 630, the number is divisible by 2 as the last digit is 0.
The sum of digits is 6+3+0 = 9, which is also divisible by 3.
Hence 630 is divisible by 6.
Divisibility Rules for 7
The rule for divisibility by 7 is given below:
Divisibility rules for 7
Example: Is 1073 divisible by 7?
From the rule stated remove 3 from the number and double it, which becomes 6.
Remaining number becomes 107, so 107-6 = 101.
Repeating the process one more times, we have 1 x 2 = 2.
Remaining number 10 – 2 = 8.
As 8 is not divisible by 7, hence the number 1073 is not divisible by 7.
Divisibility by 8
If the last three digits of a number are divisible by 8, then the number is completely divisible by 8.
Example: Take number 24344. Consider the last two digits i.e. 344. As 344 is divisible by 8, the original number 24344 is also divisible by 8.
Divisibility by 9
The rule for divisibility by 9 is similar to divisibility rule for 3. That is, if the sum of digits of the number is divisible by 9, then the number itself is divisible by 9.
Example: Consider 78532, as the sum of its digits (7+8+5+3+2) is 25, which is not divisible by 9, hence 78532 is not divisible by 9
Divisibility by 10
Divisibility rule for 10 states that any number whose last digit is 0, is divisible by 10.
hope it may help u.
please mark it as a brainlist answer please