5th term of an ap is equal to 3 times the 2nd term if 7th term is 4 less than two times the 4th term, find the 12th term
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a
3
=7 a
7
=3a
3
+2
a
7
=3×7+2=23
a+2d=7→(1)
a+6d=23→(2)
__________________
−4d=16
d=4→(3)
Sub (3) in (1)
a+2×4=7
a+8=7⇒a=−1
S
n
=
2
n
(2a+(n−1)d)
S
20
=
2
20
(2×−1+(20−1)4)
S
20
=10(76−2)
S
20
=10×740
S
20
=740
NOBITA221✔
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