Question

5x+1/3x=4

9x2+1/25x2=?​

Answer 1

Given Equation:-

• $5x+\dfrac{1}{3x} =4$ ...[I]

Point of the Question.

The question's point is multiplying $\dfrac{3}{5}$ on both sides. So let's do it!

Solution.

Multiply $\dfrac{3}{5}$ to the equation [I]

$\therefore 3x+\dfrac{1}{5x} =\dfrac{12}{5}$ ...[II]

Square both sides of [II]

$(3x+\dfrac{1}{5x} )^2=(\dfrac{12}{5} )^2$

$\rightarrow 9x^2+2\times \dfrac{3x}{5x} +\dfrac{1}{25x^2} =\dfrac{144}{25}$

$\rightarrow 9x^2+\dfrac{6}{5} +\dfrac{1}{25x^2} =\dfrac{144}{25}$

$\rightarrow 9x^2+\dfrac{1}{25x^2} =\dfrac{144-30}{25}$

$\therefore 9x^2+\dfrac{1}{25x^2} =\boxed{\dfrac{114}{25}}$

Hope you understood.

Answer 2

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‏‏‎❥SEE ATTACHMENT

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hope it helps