Question

(5x-1) (x+3)=(x-5)(5x+1)+40 find the value of x with process

Answer 1

( 5x - 1 ) ( x + 3 ) = ( x - 5 ) ( 5x + 1 ) + 40

( 5x ) ( x ) + ( 5x ) ( 3 ) + ( -1 ) ( x ) + ( -1 ) ( 3 )

5x² + 15x - x - 3 = ( 5x ) ( x ) + ( 1 ) ( x ) + ( 5x ) ( -5 ) + ( -5 ) ( -1 ) + 40

5x² + 15x - x - 3 = 5x² + x - 25x - 5 + 40

5x² - 5x² + 14x + 24x = 38

38x = 38

x = ( 38 ) ÷ ( 38 )

x = 1

Answer 2

Answer:

Concept:

• The algebraic expression should typically take one of the following forms: addition, subtraction, multiplication, or division.
• Bring the variable to the left and the remaining values to the right to determine the value of x.
• To determine the outcome, simplify the values.

Step-by-step explanation:

Given:

The given equation is $(5x-1) (x+3)=(x-5)(5x+1)+40$.

To Find:

We need to find the value of x.

Solution:

We need to simplify the given equation,

$(5x-1) (x+3)=(x-5)(5x+1)+40$

By Simplifying,

$(5x*x) + (5x*3)-(1*x)- (3*1) = (x*5x)+(x+1)-(5*5x)-(5*1)+40$

⇒  $5x^{2} +15x-x-3= 5x^{2} +x-25x-5+40$

⇒  $5x^{2} +15x-x-3 -5x^{2} -x+25x+5= 40$

⇒  $5x^{2} +14x-3 -5x^{2} +24x+5= 40$

⇒  $5x^{2} +(14+24)x-5x^{2} +2= 40$

⇒  $5x^{2} +38x-5x^{2} +2= 40$

⇒  $38x+2= 40$

⇒  $38x=40-2$

⇒  $38x=38$

⇒  $x=\frac{38}{38}$

⇒  $x=1$

Therefore, the value of $x$ is $1.$

#SPJ2