5x+10y-7 (x+2y)^2 solve this question
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see my attachment. hope it will help yo
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The correct answer will be "-7x²-28y²+5x+10y-28xy=0". Further explanation is given below.
Step-by-step explanation:
Given equation is:
5x+10y-7(x+2y)²=0
On solving the bracket, we get
⇒ 5x+10y-7(x²+4y²+4xy)=0
∵ (a+b)² = a²+b²+2ab
On multiplying "-" sign into the bracket, we get
⇒ 5x+10y-7x²-28y²-28xy=0
⇒ -7x²-28y²+5x+10y-28xy=0
Learn more:
Solve with process...
https://brainly.in/question/3818819
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