Question

-5x^2+10x-5 =0 find x value ​

Answer 1

Answer: 1

Concept: This question is from the 'Quadratic Equation'. An equation that is in the form of $ax^{2} +bx+c=0$ is called a quadratic equation where x is variable. We can find out the value of 'x' by the following method:

1. Factorization

2. Quadratic or Shridharacharya Formula

3. Making a perfect square

Here we will use the factorization method

Given: $-5x^{2} +10x-5=0$

To find: Find the value of 'x'

Solution:

$-5x^{2}+10x-5=0$

Divide by -5 into both sides

 $x^{2} -2x+1=0$

⇒ $x^{2} -x-x+1=0$

⇒ $x(x-1)-1(x-1)=0$

⇒ $(x-1)(x-1)=0$

⇒$x=1$

Hence the value of x is 1