Question

5x-2/3+4x+3/-2=3x+19/2​

Answer 1

SOLUTION

TO SOLVE

$\displaystyle \sf{ \frac{5x - 2}{3} + \frac{4x + 3}{ - 2} = \frac{3x + 19}{2} }$

EVALUATION

Here the given equation equation is

$\displaystyle \sf{ \frac{5x - 2}{3} + \frac{4x + 3}{ - 2} = \frac{3x + 19}{2} }$

$\displaystyle \sf{ \implies \: \frac{5x - 2}{3} - \frac{4x + 3}{ 2} = \frac{3x + 19}{2} }$

$\displaystyle \sf{ \implies \: \frac{10x - 4 - 12x - 9}{6} = \frac{3x + 19}{2} }$

$\displaystyle \sf{ \implies \: \frac{ - 2x - 13}{6} = \frac{3x + 19}{2} }$

$\displaystyle \sf{ \implies \: \frac{ - 2x - 13}{3} = {3x + 19} }$

$\displaystyle \sf{ \implies \: - 2x - 13 = 9x + 57 }$

$\displaystyle \sf{ \implies \: - 2x -9x = 57 + 13 }$

$\displaystyle \sf{ \implies \: - 11x = 70}$

$\displaystyle \sf{ \implies \: x = - \frac{70}{11} }$

FINAL ANSWER

Hence the required solution is

$\displaystyle \sf{ \: x = - \frac{70}{11} }$

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