Question

5x^ 2-3x-2=0quadratic equation by factorization​

Answer 1

Answer:

5x^2-5x+2x-2=0

5x(x-1)+2(x-1)=0

(5x+2)(x-1)=0

x=1

x=-2/5

Answer 2

SOLUTION

$= > 5{x}^{2} - 3x - 2 = 0 \\ = >5 {x}^{2} - 5x + 2x - 2 = 0 \\ = > 5x(x - 1) + 2(x - 1) = 0 \\ = > (x - 1) \: \: (5x + 2) = 0 \\ = > x - 1 = 0 \: \: \: or \: \: 5x + 2 = 0 \\ = > x = 1 \: \: \: or \: \: \: x = - \frac{2}{5}$

hope it helps ☺️