Question

(5x^2-3y^2):xy=11:2,find x,y​

Answer 1

Answer:

Step-by-step explanation:

first step, cross multiply:

2(5x^2-3y^2) = 11xy.

second step, remove bracket:

10x^2-6y^2 = 11xy

third step, "follow the step"

10x^2 - 11xy -6y^2 = 0

fourth step, quadritic equation by middle term break:

10x^2 - 4xy - 15xy - 6y^2 =0

=>2x(5x-2y) - 3y(5x- 2y) =0

=>(2x-3Y)(5x-2y) = 0

therefore  x = 3y/2 or 2y/5

you can find y in te same way