Question

`(5x-2)/(4)-(1)/(5)(3x-(2-x)/(6))=(12)/(6​

Answer 1

Step-by-step explanation:

5x-2/3/6x+3x^2/6

(5x-2)6/(6x+3x^2)3

30x-12/18x+9x^2=12/6

180x-72=216x+108x^2

36x+108x^2-72=0

54x^2+18x-36=0

27x^2+9x-18=0

9x^2+3x-6=0

3(3x^2+x-2)=0

3x^2+x-2=0

3x^2+3x-2x-2=0

3x(x+1)-2(x+1)=0

(3x-2)=0 and (x+1)=0

3x=2 and x=-1

x=2/3 Or x=-1

Answer 2

Answer:

hey mate here is your program

Step-by-step explanation:

{

public static void main (String[]args)

{

Scanner sc = new Scanner(System.in);

System.out.println(" Enter a month number");

int n=sc.nextInt();

if(n==1)

System.out.println("January");

else if(n==2)

System.out.println("Februry");

else if(n==3)

System.out.println("March");

else if(n==4)

System.out.println("April");

else if(n==5)

System.out.println("May");

else if(n==6)

System.out.println("june");

else if(n==7)

System.out.println("July");

else if (n==8)

System.out.println("August");

else if(n==9)

System.out.println("September");

else if(n==10)

System.out.println("October");

else if(n==11)

System.out.println("November");

else if(n==12)

System.out.println("December");

}

}