5x^2=4x+7
Solve by Completing the square method!
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GIVEN
5x^2=4x+7
5x^2 - 4x - 7 = 0
Multiply by 5
25x^2 - 20x - 35 = 0
2ab = - 20
Where a = 5
10b = - 20
b = - 2
(5x - 2)^2 + (-2)^2 - 35 = 0
(5x - 2)^2 - 4 - 35 = 0
(5x - 2)^2 = 39
![5x \: - 2 = + - \sqrt{39 } \\ 5x =2 + - \sqrt{39} \\ x = \frac{2 + - \sqrt{39} }{5} \\ take \: + \\ x = \frac{2 + \sqrt{39} }{5} \\ take \: - \\ x = \frac{2 - \sqrt{39} }{5} 5x \: - 2 = + - \sqrt{39 } \\ 5x =2 + - \sqrt{39} \\ x = \frac{2 + - \sqrt{39} }{5} \\ take \: + \\ x = \frac{2 + \sqrt{39} }{5} \\ take \: - \\ x = \frac{2 - \sqrt{39} }{5}](https://tex.z-dn.net/?f=5x+%5C%3A++-+2+%3D+++%2B++-+%5Csqrt%7B39+%7D++%5C%5C+5x+%3D2+%2B++-++%5Csqrt%7B39%7D+++%5C%5C+x+%3D++%5Cfrac%7B2+%2B++-++%5Csqrt%7B39%7D+%7D%7B5%7D++%5C%5C+take+%5C%3A++%2B++%5C%5C+x+%3D++%5Cfrac%7B2+%2B++%5Csqrt%7B39%7D+%7D%7B5%7D++%5C%5C+take+%5C%3A++-++%5C%5C+x+%3D++%5Cfrac%7B2+-++%5Csqrt%7B39%7D+%7D%7B5%7D+)
5x^2=4x+7
5x^2 - 4x - 7 = 0
Multiply by 5
25x^2 - 20x - 35 = 0
2ab = - 20
Where a = 5
10b = - 20
b = - 2
(5x - 2)^2 + (-2)^2 - 35 = 0
(5x - 2)^2 - 4 - 35 = 0
(5x - 2)^2 = 39
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