Question

5x^2-7x-5=0 by completing square method

Answer 1

Answer:

Dividing both sides by 5, we get

${x}^{2} - \frac{7}{5} x - 1 = 0$

${x}^{2} - 2x \frac{7}{10} + ( \frac{7}{10} ) {}^{2} - 1 - \frac{49}{100} = 0$

$(x - \frac{7}{10} ) {}^{2} = \frac{149}{100}$

$x - \frac{7}{10} = \frac{ \sqrt{149} }{10} \: or \: - \frac{ \sqrt{149} }{10}$

$x = \frac{7 + \sqrt{149} }{10} \: or \: \frac{7 - \sqrt{149} }{10}$

Ans.