Question

5x^2-7x-6 find the roots of quadratic equation if they exist​

Answer 1

Answer:

-3/5,2

Step-by-step explanation:

By splitting the middle term method,

Product of the constant and x^2 term

                     = 5x^2 * -6   = -30x^2

         Splitting -7x in two numbers so that their product is -30x^2

                    Tharerfore, -10x + 3x = -7x

                                        -10x * 3x = -30x^2

        5x^2-10x+3x-6=0

        5x(x-2)+3(x-2)=0

        (5x+3)(x-2)=0

        therefore, 5x+3=0

                          5x=-3

                          x=-3/5

                      x-2=0

                      x=2

      Therefore, the roots are -3/5 and 2