Question

√5x^2- x - √5 = 0 find discriminant ​

Answer 1

Answer:

Discriminant = 21

Step-by-step explanation:

Discriminant of a quadratic equation

$ax^{2} +bx+c=0$

is given by,

$D = b^{2} -4ac$

Given equation is,

$\sqrt{5} x^{2} - x - \sqrt{5} =0$

Here,

$a = \sqrt{5}\\ b = -1\\c = -\sqrt{5}$

So,

$D = (-1)^{2} - 4 * \sqrt{5} *(-\sqrt{5} )\\D = 1 + (4*5)\\D = 1 + 20\\D = 21$