Question

5x-2y=0, 4x+10y=1 solve by elimination method​

Answer 1

Answer:

x = 1/29

y = 5/58

Step-by-step explanation:

5x - 2y = 0.....(i)

4x + 10y = 1.....(ii)

Let us multiply eq. (i) by 5

=> 5 × (5x - 2y = 0)

=> 25x - 10y = 0.....(iii)

Now (ii) and (iii)

=>

4x + 10y = 1

+ 25x ± 10y = 0

= 29x = 1

=> x = 1/29

Put the value of x in eq. (i)

5x - 2y = 0

=> 5(1/29) - 2y = 0

=> 5/29 - 2y = 0

=> - 2y = -5/29

=> 2y = 5/29

=> y = 5/29 ÷ 2

=> y = 5/29×2

=> y = 5/58

Hence the value of x = 1/29 and value of y = 5/58.

hope it helps.

Answer 2

Step-by-step explanation:

$5x - 2y = 0 \: \: \: \: \: \: \: \: \: \: \: (1)$

$4x - 10y = 1 \: \: \: \: \: \: \: \: \: \: \: (2)$

Multiplying equation 1 with 5 and 2 with 1

Adding equation 1 and 2

$25x - \not10y = 0 \\ 4x - \not10y = 1 \\ \underline{\: \: \: - \: \: \: \: \: \: \: - \: \: \: \: \: - } \\ {29x = 1}$

$x = \frac{1}{29}$

On putting the values of x in equation 1

$5( \frac{1}{29} ) - 2y = 0$

$\frac{5 - 58y}{29} = 0$

$5 - 58y = 0$

$\not - 58y = \not - 5$

$y = \frac{5}{58}$