5x – 2y = 1; 3x + 5y = 13
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by substitution method
5x-2y=1. (1)
3x+5y=13. (2)
x=1+2y/5. (3)
put value of x in eq 2 we get
3×(1+2y/5)+5y=13
3+6y/5+5y=13
3+6y+25y/5=13
3+31y=13×5
31y=65-3
y=62/31
y=2
put the value of y in eq 3 we get
x=1+2y/5
x=1+2×2/5
x=1+4/5
x=5/5
x=1
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