Question

5x-2y+3=0, If (0, a) and (b, 0) are the solutions of the given linear equation. Find ‘a’ and ‘b’.

Answer 1

$\bold{Answer :}$

Given equation is

5x - 2y + 3 = 0 ...(i)

Since, (0, a) is a solution of (i),

5 (0) - 2 (a) + 3 = 0

or, 0 - 2a + 3 = 0

or, 2a = 3

or, a = 3/2

Again (b, 0) is a solution of (i); so,

5 (b) - 2 (0) + 3 = 0

or, 5b - 0 + 3 = 0

or, 5b = - 3

or, b = - 3/5

Therefore, the value of a is 3/2 and that of b is (- 3/5).

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Answer 2

Given that ( 0 , a ) and ( b , 0 ) are the

solutions of 5x - 2y + 3 = 0

i ) Substitute ( 0 , a ) in the equation ,

5 × 0 - 2 × a + 3 = 0

=> -2a = -3

=> a = ( -3 )/( -2 )

a = 3/2

ii ) Substitute ( b , 0 ) in the equation ,

5 × b - 2 × 0 + 3 = 0

=> 5b + 3 = 0

=> 5b = -3

b = -3/5

Therefore ,

a = 3/2 and b = -3/5

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