Math, asked by vijayapichai090, 10 months ago

5x - 3/2 = 2x+7/2 solve the equation​

Answers

Answered by jagadasatapathy
5

Answer:

5/3

Step-by-step explanation:

5x -3/2 =2x +7/2

=5x -2x=7/2 +3/2

=3x =10/2

=x=10/6=5/3 I hope it will help you

Answered by spacelover123
8

Let's solve your equation step-by-step.

\sf 5x-\frac{3}{2}=2x+\frac{7}{2}

Step 1: Simplify both sides of the equation.

\sf 5x+\frac{-3}{2}=2x+\frac{7}{2}

Step 2: Subtract 2x from both sides.

\sf 5x+\frac{-3}{2}-2x=2x+\frac{7}{2}-2x

\sf 3x+\frac{-3}{2}=\frac{7}{2}

Step 3: Add \sf \frac{3}{2} to both sides.

\sf 3x+\frac{-3}{2}+\frac{3}{2} =\frac{7}{2}+\frac{3}{2}

\sf 3x=5

Step 4: Divide both sides by 3

\sf \frac{3x}{3}=\frac{5}{3}

\sf x = \frac{5}{3}

Verification if the value of 'x' is correct.

\sf 5x-\frac{3}{2}=2x+\frac{7}{2}

\sf (5\times \frac{5}{3})  -\frac{3}{2}=(2\times \frac{5}{3})  +\frac{7}{2}

\sf  \frac{25}{3}  -\frac{3}{2}=\frac{10}{3} +\frac{7}{2}

\sf  \frac{25\times 2 }{3\times 2 }  -\frac{3\times 3 }{2\times 3 }=\frac{10\times 2 }{3\times 2} +\frac{7\times 3}{2\times 3 }

\sf  \frac{50}{6 }  -\frac{9 }{6}=\frac{20 }{6} +\frac{21}{6}

\sf  \frac{41}{6}=\frac{41}{6}

\sf \bf  x = \frac{5}{3} in the equation ⇒ \sf \bf  5x-\frac{3}{2}=2x+\frac{7}{2}

Additional Information :)

An expression is a simple mathematical statement which doesn't consist of an equal sign.

For example =>  \sf x+9

An equation is a mathematical statement which consists of an equal sign.

For example => \sf  2x+88=980

A variable is an unknown value that is mostly represented in the form of small English alphabets. We use variables in an algebraic equation and algebraic expression.

A constant is a proper value which is mostly represented in the form of numbers. We use constants in an algebraic equation and algebraic expression.

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