Question

(5x-3)/3 - (3x-5)/10 = (8x-8)/5 + 1/20

Answer 1

$\color {violet} \boxed{ \colorbox{black}{ \sf{answer}}}$

$x = \frac{9}{2}$

$\color {violet} \boxed{ \colorbox{black}{ \sf{explanation}}}$

$\frac{(5x - 3)}{3} - \frac{(3x - 5)}{10} = \frac{(8x - 8)}{5} + \frac{1}{20} \\ = > \frac{50x - 30 - 9x + 15}{30} = \frac{32x - 32 + 1}{20} \\ = > \frac{41x - 15}{30} = \frac{32x - 31}{20} \\ = > 2(41x - 15) = 3(32x - 31) \\ = > 82x - 30 = 96x - 93 \\ = > 82x - 96x = - 93 + 30 \\ = > - 14x = - 63 \\ = > x = \frac{ - 63}{ - 14} = \frac{9}{2}$

hope it helps.. :)