Question

5x - 3 /6 - 3x + 4 / 4 =3/10 - 2x​

Answer 1

Question

Find 'x' in this equation ⇒ $5x-\frac{3}{6}-3x+\frac{4}{4}=\frac{3}{10}-2x$

$\rule{300}{1}$

Answer

Let's solve your equation step-by-step.

$5x-\frac{3}{6}-3x+\frac{4}{4}=\frac{3}{10}-2x$

Step 1: Simplify both sides of the equation.

$5x-\frac{3}{6}-3x+\frac{4}{4}=\frac{3}{10}-2x$

$5x+\frac{-1}{2}+-3x+1=\frac{3}{10}+-2x$

(Combine Like Terms)

$(5x+-3x)+(\frac{-1}{2}+1) = -2x+\frac{3}{10}$

$2x+\frac{1}{2}=-2x+\frac{3}{10}$

Step 2: Add 2x to both sides.

$2x+\frac{1}{2}+2x=-2x+\frac{3}{10}+2x$

$4x+\frac{1}{2}=\frac{3}{10}$

Step 3: Subtract $\frac{1}{2}$ from both sides.

$4x+\frac{1}{2}-\frac{1}{2} =\frac{3}{10}-\frac{1}{2}$

$4x=\frac{-1}{5}$

Step 4: Divide both sides by 4.

$4x\div 4 =\frac{-1}{5}\div 4$

$x= \frac{-1}{5}\times\frac{1}{4}$

$x=\frac{-1}{20}$

$\bf\therefore x=\frac{-1}{20} \ in\ the \ equation =>\ 5x-\frac{3}{6}-3x+\frac{4}{4}=\frac{3}{10}-2x$

$\rule{300}{1}$