Question

(5x-3x) (x+4)-(2x +5)(3x-4)​

Answer 1

Answer:

Step-by-step explanation:

5x^2-3x^2+20x-12x-6x+8x-15x+20

=2x^2-5x+20

Now by using quadratic equation,

$\alpha$=-(-5)+$\sqrt{25-160}$/4

 =5+$\sqrt{-135}$/4

As we can see that one of the root is imaginary, the other will also be imaginary and it will be 5-$\sqrt{-135}$/4.

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Answer 2

Answer:

${ - 4x}^{2} + 15x + 20$

Step-by-step explanation:

(5x-3x)(x+4)-(2x+5)(3x-4) \\

=2x(x+4)-(2x+5)(3x-4) \\ = ( {2x}^{2} + 8x) - ( {6x}^{2} -8x + 15x - 20) \\ = ( {2x}^{2} + 8x) - ( {6x}^{2} + 7x - 20) \\ = {2x}^{2} + 8x \: - {6x}^{2} + 7x + 20 \\ = - {4x}^{2} + 15x \: + 20 [/tex]

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