Math, asked by divyeshkher19, 8 months ago

5x-3y=0,3x-5y=16 by substitution method​

Answers

Answered by NishuNain
14

Answer:

check the attachment

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Attachments:
Answered by harsh228384
2

Answer:

-5,-3

Step-by-step explanation:

5x-3y=0

5x=3y

x=3y

 \frac{3y}{5}

x=

3x-5y=16

3(3y/5)-5y=10

9y-25y=80 (multiplying equation with 5)

-16y=80

y=80/-16

y= -5

Putting y= -5 in x=3y/5

x=3(-5)/5

x= -15/5

x= -3

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